Purchase Solution

Education - Professional Dev

Not what you're looking for?

Ask Custom Question

What are the pros and cons of individualized vs. school-based vs. district-wide professional development?

Purchase this Solution
Solution Summary

Discusses individualized/school-based, and district wide professional development.

Solution Preview

Some differences that are apparent between individualized and district-wide professional development exist, but both seek to ensure quality professional development for all if their employees. Individualized plans are created on a school-by-school basis with comprehensive programs implemented by these individual schools. These plans are characterized by development plans that include in the developmental process teachers who work collectively to create a plan that is driven by data regarding the needs facing the individual schools (WWW2, 2012).

These individual plans align all of the activities such as training, seminars, and workshops with the instructional focus posited by the teachers while pooling their available ...

Solution provided by:
Stephen Washington, MS
Education
  • BS, Sam Houston State University, 1903 University Avenue, Huntsville, Tx 77340
  • MS, Prairie View A&M University
Recent Feedback
  • "awesome"
  • "awesome"
  • "Awesome appreciate the assistance."
  • "Thanks awesome. more to follow"
  • "awesome, Thanks for the assistance"
Purchase this Solution
Free BrainMass Quizzes
Classroom Management

This quiz correlates with my eBook titled "Everything You Need to Know About Classroom Management." Test your skills on the benefits of sound classroom management practices.

Verbals

This quiz focuses on recognizing verbals. It requires understanding the differences between a gerund and participle. Most often, gerunds end in "ing" and act as a noun. Participles mostly end in "ing", but act as adjectives.

Common Core State Standards

Media portrays a love vs. hate relationship regarding the Common Core State Standards. How much do you know about the CCSS? This quiz provides a basic understanding of the establishment of the Common Core.

Grit and Perseverance in Children

Building small humans is a daunting task. There is nothing more important than our impact on those around us, especially the smallest ones. This quiz offers a brief overview of different parenting modes and how to provide experiences for children to thrive!

Empowering Children

Asking questions is a technique to promote self-confidence for children. Practice replacing statements and directives with questions to encourage thinking skills.

View More Free Quizzes
Related BrainMass Solutions

  • Brazil's Growth Rate, Age Profile, Health and Employment

    The country's education comprises of nine years of mandatory elementary education (to age 14) and three years of secondary education.

  • Problem scenario

    We also assume that based on historical data, the average earning of an MBA is $80,000, with std. dev. of $10,000.

  • Joint Destiny - Random Variable

    N(mew^2,check mark std, dev.) b.) N(mew^2, std. dev.^2) c.) N(check mark mew, std. dev.^2) d.) X^2(1)

  • Boot floppy

    Slackware only: Use /dev/fd0u1440 instead of /dev/fd0H1440. With older versions, try /dev/fd0h1440, with a lower case h. SuSE only: Use /dev/fd0u1440 instead of /dev/fd0H1440.

  • Statistics Homework

    X Is there a correlation of job satisfaction to education?

  • Optimal risky portfolio

    .= 0.24 Portfolio B: The weight for S1 and S2 = 0.4 and 0.6; Expected return = 0.18; Standard Dev.= 0.31 Portfolio C: The weight for S1 and S2 = 0.5 and 0.5; Expected return = 0.19; Standard Dev.= 0.35 Portfolio D: The weight for S1 and S2 = 0.9

  • Average Daily Sodium Intake

    Mean = 3120 Std Dev of sample = 800 n = 25 Std dev of population = sample Std dev/ n^.5 = 800/25^.5 = 160 Z value for 98% confidence = 2.054 98% CI = ( Mean- Z*Std Dev , Mean + Z*std dev) = (2791.4,3448.6).

  • Calculating the sample size given a significance level

    Lower Limit = Mean - Z*Std Dev/n^.5
    Upper Limit = Mean + Z*Std Dev/n^.5

    So Range = Upper Limit - Lower Limit
    L = 2*Z*Std Dev/n^.5

    Given L = 100 , Std Dev = 1050 and from tables Z = 1.28....

  • Confidence interval, how many executives should be interviewed

    Confidence Interval = [mean - z * std dev / sqrt(n), mean + z * std dev / sqrt(n)] , where z * std dev / sqrt(n) is the error so we have error = 2*z*std dev / sqrt(n) .25 = 2 * 1.96*300 / sqrt(n) n= 69 The expert uses 95% confidence intervals

  • Binomial Distribution

    = Mean + std dev *z = 74 + 2.58x4.38 = 85.3 d. what is the upper limit for #15 if the sample size is 64? = Mean - std dev *z = 74 - 2.58x4.38 = 62.7

View More Related Solutions