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Statistical Table for OTA #104811 or whoever can answer

I am having trouble how to go about comparing my computer with the one given in this exercise. See the instructions below and my attempt to do this table. Please also provide the best way to approach this table with an example. Help! Thanks.
In 1964 one of the most popular business computers was the IBM 1401.
IBM built thousands. You can see a picture of a 1401 at:
http://www.ed-thelen.org/comp-hist/BRL64-i.html

You have heard many times how much more powerful your PC is than the old
computers. In this exercise you are going to compare your PC to the IBM
1401.

I want you to use the statistics below to determine:

A. How many 1401 computers would be required to match the processing
speed of your PC, how much they would cost, what would be the monthly maintenance
charges and the floor space required to house the devices. Ignore any
instruction width considerations. Compare raw speed only.

B. How many memory (core) modules would be required to match the memory
on you PC, how much they would cost, what would be the monthly maintenance charges
and the floor space required to house the devices.

C. How many disk drives would be required to match the internal disk
drive on your PC, how much they would cost, what would be the monthly maintenance
charges and the floor space required to house the devices.

D. How many 1403 Printer printers will be required to match the speed of your printer, how
much they would cost, what would be the monthly maintenance charges and the floor
space required to house the devices. (If you do not have a printer do the comparison assuming

you have a 6 page-per-minute printer.

E. What is the combined total cost, monthly maintenance charges and floor space required to

have 1401 components to match your PC's capabilities?

Note: IBM's name for the computer was "1401". Other components of the 1401 computer

were based upon the 1401 name -- such as the 1403 printer, 1405 disk drive, etc.)

Data:

IBM 1401 Computer. Processor speed: 1,000/sec, Cost $67,000, Maintenance
$1,600/month, Floor space 80 ft sq

IBM core memory modules: Memory 16,000 bits. Cost $84,000, Maintenance
$1,200/month, floor space 1- ft sq

IBM 1405 Disk drive: Capacity 20,000,000 characters, Cost $42,000,
Maintenance $1,800/month, Floor space 8 ft sq

IBM 1403 Printer: 120 pages/minute, cost $33,000, Maintenance $725/month,
Floor space 40 ft sq.

Assume that it is possible to connect all of these devices into one
multi-computer configuration.

Ignore electrical power, air conditioning, and other costs.

Please present you answers in a table:

For each of the four devices, your table should include at least the
following items:

a. You PC's capacity
b The number of IBM 1400 units required to duplicate your PC's capacity

c. Total purchase cost
d. Total monthly maintenance

e. Floor space in Square feet.

f. Floor space in some unit other than ft sq -- such as the how many
living rooms in your house would be required to hold the equipment, or
football fields, or aircraft carrier decks, etc.

You table should provide purchase cost, maintenance cost and floor space totals.

What was the surprise device in the calculation?

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Ok This is where I am so far and how I got there so you can do it yourself for your computer.

Part of this assignment is to learn how to do some research and make some ball park estimates.

I looked at the manufacturer or vendor and model of the computer I generally use at work and recorded that information for the computer and the printer.

IBM makes my computer and the model is 6791 KAV....so then I typed in IBM in the search engine and picked the home site. Then I typed in 6791 and found NETVISTA 6791 KAV...Net vista was also on the front of the computer box.

I poked around until I found the product data sheet and I compared that to the control panel system query for WIN 2000 on the computer and I found the computer parameters matching to your data comparison requirements.

Processor Speed Real is 1.794 GHz and list is 1.8 GHz Hz = cycles/sec
Space as measured with a dollar bill 6.5 " is 14" x 14 " ....I am calling that 1.4 sq feet.

1.794 GHz/1 kHz = 1,794,000 IBM 1401 processors

1,794,000 x 80 sq ft = 143,520,000 ...

$2.19