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The Direction of Passing Parameters in C

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Let the function fun be defined as:

int fun(int *k) {
*k += 4;
return 3 * (*k) - 1;
}

Suppose fun is used in a program as follows:

void main() {
int I = 10, j = 10, sum1, sum2;
sum1 = (I / 2) + fun(&i);
sum2 - fun(&j) + (j / 2);
}

What are the values of sum1 and sum2?
a. If the operands in the expressions are evaluated left to right?
b. If the operands in the expressions are evaluated right to left?

Now the answers are: Let the function fun be defined as:

int fun(int *k) {
*k += 4;
return 3 * (*k) - 1;
}

Suppose fun is used in a program as follows:

void main() {
int I = 10, j = 10, sum1, sum2;
sum1 = (I / 2) + fun(&i);
sum2 - fun(&j) + (j / 2);
}

What are the values of sum1 and sum2?
a. If the operands in the expressions are evaluated left to right?
b. If the operands in the expressions are evaluated right to left? Let the function fun be defined as

int fun(int *k) {
*k += 4;
return 3 * (*k) - 1;
}

Suppose fun is used in a program as follows:

void main() {
int I = 10, j = 10, sum1, sum2;
sum1 = (I / 2) + fun(&i);
sum2 - fun(&j) + (j / 2);
}

What are the values of sum1 and sum2?
a. If the operands in the expressions are evaluated left to right? Sum1=46, Sum2=48
b. If the operands in the expressions are evaluated right to left? Sum1=48, Sum2=46

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Solution Summary

This solution provides a detailed, step by step response illustrating how a parameter will change in a C function by value or address, and direction as well.

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a. If the operands in the expressions are evaluated left to right?

sum1 = 46;
sum2 = 48;

Code:

int fun(int *k) {
*k += 4;
return 3 * (*k) - 1;
}

void main()
{
int i = 10, ...

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