Working with balanced chemical reactions
7) Which would be used up first? How many grams of Cl2 will be produced?
TiO2 + HCl = TiCl2 + Cl2 + H2O if 0.86 mole of TiO2 and 1.5 lbs of HCl react
https://brainmass.com/chemistry/stoichiometry/working-balanced-chemical-reactions-16445
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Our balanced reaction is,
TiO2 + 4HCl ==> TiCl2 + Cl2 + 2H2O
That is 1 mole TiO2 requires 4 moles of HCL to produce 1 mole of Cl2
Mol wt of TiO2 = 79.9 g/mole
Mol wt 0f HCl = 36.46 g/mole
1 POUND = 2.2 KILOGRAMS, 1.5 lbs of HCl = 2.2*1.5 *10^3 g = 3.3*10^3 g
That is number of moles of HCL = 3.3*10^3/36.46 = 90.51 moles.
We have 0.86 moles of TiO2 and 90.51 moles of HCl.
1 mole TiO2 requires 4 moles of HCL.
Therefore, 0.86 moles of TiO2 requires 4*0.86 moles of HCl
That is 3.44 moles of HCl.
Therefore TiO2 will be used up first.----Ans
Now, 1 mole TiO2 gives 1 mole of Cl2.
Therefore 0.86 mole of TiO2 gives 0.86 moles of Cl2 = 0.86 * 70.9 g of Cl2 = 60.974 g of Cl2 ----Ans
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