Stoichiometry: Sodium Iodide and Mercury Nitrate
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Given that 24.0mL of 0.170 M sodium iodide reacts with 0.209M mercury(II) nitrate solution according to the unbalanced equation:
Hg(NO3)2 + NaI gives HgI2 + NaNO3
a) What volume of Hg(NO3)2 is required for complete precipitation?
b) What is the mass of HgI2 precipitate?
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The solution is attached below in two formats. One is in Word XP Format, while the other is in Adobe pdf format. Therefore, you can choose the format that is most suitable to you. The solution also outlines a five step strategy for solving A, a three step strategy for solving B and complete calculations, answers and explanation formatted in the attached document.
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