moles P = mass / atomic mass = 20.2 g(1 mole)/(30.974 g) = 0.652 mole P
moles Cl2 = mass / molar mass = 78.2 g(1 mole)/(70.906 g) = 1.103 mole Cl2
the following reactions will take place:
2 P + 3 Cl2 --> 2 PCl3 and PCl3 + Cl2 --> PCl5
The reaction should first produce PCl3 then the excess Cl2 will allow production of PCl5. We will ...
The following stoichiometric problem has been solved stepwise so one can understand the solution and use similar methodology to solve similar problems.