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Calculating molarity in an acid/base titration.

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If 25.00 mL of 1.000M HNO^3 is titrated to a neutral endpoint with 36.97 mL of NaOH solution, what is the molarity of the NaOH solution?

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Solution Summary

The general formula for this type of question is M(base)V(base)=M(acid)V(acid).

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In order to titrate the acid to neutral endpoint, you must add equal moles of base to neutralize the acid. Since NaOH gives off one OH- group and HNO3 gives off one H+, the stoichiometry between base and acid is 1:1. Therefore, at neutral endpoint, moles of acid is equal to the moles ...

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