Dry air near sea level has the following composition by volume: N_2, 78.08%; O_2 20.94%; Ar, 0.93%; CO_2 0.05%. the atmospheric pressure is 1.00 atm. calculate the partial pressure of each gas in atm and the concentration of each gas in moles per liter at 0 degrees C.

Solution Preview

N_2 = 78.08 % = 0.7808 L/L
O_2 = 20.94 % = 0.2094 L/L
Ar = 0.93 % = 0.0093 L/L
CO_2 = 0.05 % = 0.0005 L/L
P = P1 + P2 + P3 + P4
because,
PV = nRT
If V = 1 L
concentrations of each ...

Solution Summary

The solution looks at the concentrations of gases and applies the idea gas law and Dalton's law to find the answer.

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