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Chemistry - Mass Ratio, Atoms and Density

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When barium (Ba) reacts with sulfur (S) to form barium sulfide (BaS), each Ba atom reacts with an S atom. If 2.40 cm3 of Ba reacts with 1.65 cm3 of S, are there enough Ba atoms to react with the S atoms (d of Ba = 3.51 g/cm3; d of S = 2.07 g/cm3)?

For barium sulfide, calculate the barium to sulfur mass ratio.

From the information in the question, calculate the barium to sulfur mass ratio.

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Solution Summary

Mass ratio, atoms and density are examined. A complete, neat and step-by-step solution is provided.

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(a) Mass of Ba in the reaction = volume * density = 2.40 cm^3 * 3.51 g/cm^3 = 8.424 g

Number of moles of Ba = ...

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