Electrolysis of water
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By the electrolysis of water, 11.2 L oxygen at STP was prepared.
A) What charge was required?
B)If a current of 0.5A was used how long did it take?
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Solution Summary
The solution calculates the charge required in the electrolysis of water.
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A) What charge was required?
The molar volume of any gas at STP is 22.4 L
Therefore 11.2 L of Oxygen at STP = 1/2 mole
1 molecule of Oxygen requires 4 electrons
Therefore 1 /2 mole of Oxygen requires 4 x 1/2 x 1 mole of electrons
1 mole of electrons= 96500 C
Therefore charge required= 193,000 C =4*1/2 * ...
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