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    Electrolysis of water

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    By the electrolysis of water, 11.2 L oxygen at STP was prepared.

    A) What charge was required?

    B)If a current of 0.5A was used how long did it take?

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    Solution Preview

    A) What charge was required?

    The molar volume of any gas at STP is 22.4 L
    Therefore 11.2 L of Oxygen at STP = 1/2 mole

    1 molecule of Oxygen requires 4 electrons
    Therefore 1 /2 mole of Oxygen requires 4 x 1/2 x 1 mole of electrons
    1 mole of electrons= 96500 C

    Therefore charge required= 193,000 C =4*1/2 * ...

    Solution Summary

    The solution calculates the charge required in the electrolysis of water.