Disubstituted Alkene

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• Writing Equations for Each of the Given Reagents

  Bromination of an alkene gives a 1,2 dibromoalkane. Note: If the alkene is cyclic, only the trans dibromo product is formed. f. Gives Markovnikov addition 2. See Figure 2. a. Reactant is 2-butyne.

• possible trisubstituted derivatives C6H3X2Y from the para disubstituted benzene C6H4X2

  The solution finds the possible trisubstituted derivatives C6H3X2Y whihch can be obtained from the para disubstituted benzene C6H4X2.

• Aromatic compounds - trisubstituted derivatives

  See the attached .pdf for the structures How many possible trisubstituted derivatives C6H3X2Y can be obtained from the meta disubstituted benzene C5H4X2?

• Possible Trisubstituted Derivatives

  313176 Possible Trisubstituted Derivatives How many possible trisubstituted derivatives C6H3X2Y can be obtained from the meta disubstituted benzene C6H4X2?

• Determining Compounds With and Without Spectroscopy

  If it's symmetrically split then we've got a 1,4-disubstituted benzene. If it's a big awkward looking, then we've probably got a 1,2-disubstituted ring. I'll leave that up to you to figure out.

• Electron Donor and Receptor in Metal Complexes

  to palladium If the alkene is an electron donor, would you expect the alkene in the complex to have a positive charge or a negative charge?

• Determine the Functional Group

  Therefore, this is a 1,4-disubstituted aromatic compound. Glad to help. It's not that hard once you have a little practice.

• Spectroscopy and Conversion of Alcohol

  The mass of an alcohol is 18 amu greater than the corresponding alkene. How come? Because when you dehydrate an alcohol, you lose water. This results in the alkene.

• Strain or Steric energy

  It draws the structures of alkene with cis and trans isomers and in the "zig-zag" stick conformation respectively. An alkene having cis and trans isomers are determined for strain energy.