balance an equation using the oxidation number method
How do I balance an equation using the oxidation number method?
Sn+HNO3---------->SnO2+NO2+H20
Solution Preview
When balancing redox reactions we go through several steps.
1) Find half reactions
2) Balance half reactions in both mass and charge.
3) Adjust have reactions so that electrons will cancel.
4) Add half reaction together
1) To find the half reactions we look at the reactants and products. Sn is obviously forming SnO2, and HNO3 is forming the ...
Solution Summary
It shows how to balance an equation using the oxidation number method. The solution is detailed and well presented.
2KMnO4 + 5H2O2 + 6HCl --> 5O2 + 2MnCl2 + 8H2O + 2KCl
I need to calculate thebalanced NET IONIC equation for the above reaction.
I've been usingtheoxidationnumbermethod and determined H2O2 is the reducing agent and KMnO4 is the oxidizing agent.
Mn gained 5 electrons, but I'm not sure how many electrons Oxygen gained
Hi, I am having some trouble understanding my text book. Could you explain to me how to balancethe following equations usingthe half cell method and show both their half cell reactions, including how to identify them as either oxidation or reduction reactions.
Cl2+OH^- <> Cl^-+ClO3^-+H2O
SO4^2-+I^-+H^+ <> S^2-+I2+H2O
Please see the attached file for the fully formatted problems.
Question 1.
In addition to mass balance, oxidation-reduction reactions must be balanced such that thenumber of electrons lost in theoxidation equals thenumber of electrons gained in the reduction. This balancing can be done by two methods: the half-reactio
Balancethe following equation:
Cu(s)+ AgNO3(aq) = Ag(s) + Cu(NO3)2(aq)
("s" and "aq" in parantheses refers to the phase of the reactants and products, i.e. solid and aqueous, respectively.)
What is the amount of Cu (in grams) necessary to precipitate 0.50 g of Ag in the presence of excess AgNO3?
Use the following pair of reduction half-reactions to design a galvanic cell. Then write in the proper coefficient for each of the species involved in the overall reaction. Water molecules and protons are not shown in the half-reactions, but may be needed in the overall reaction.
MnO4- (aq) --> MnO2 (s) Eo = 0.59 V
NO3- (aq) -
