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    Titration problems

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    In the reaction CaCO3 + 2HNO3 → Ca(NO3)2 + CO2 + H2O, how many milliliters of 0.1015 M HNO3 are required to react with 0.9857 grams of CaCO3?

    Find the fraction of association of a 0.120 molar solution of hydrogen cyanate.
    Ka for hydrogen cyanate = 3.30×10-4.

    A sample containing 0.2784 grams of sodium chloride (NaCl) and 0.5486 grams of aluminum chloride (AlCl3). The chloride in the sample was precipitated by the addition of 47.8 mL of a silver nitrate solution. What is the concentration of the silver nitrate solution?

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    Solution Preview

    In the reaction CaCO3 + 2HNO3 → Ca(NO3)2 + CO2 + H2O, how many milliliters of 0.1015 M HNO3 are required to react with 0.9857 grams of CaCO3?

    The given reaction is:
    CaCO3 + 2HNO3 → Ca(NO3)2 + CO2 + H2O

    From the stoichiometry of reaction, we can see that 1 mol of CaCO3 reacts with 2 moles of HNO3

    Moles of CaCO3 = mass/molar mass = 0.9857g/100.0g/mol = 0.009857 moles

    Therefore, as per equation, moles of HNO3 required = 2 x moles of CaCO3
    ...

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