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Solutions, Solubility and Concentration

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18. The chloride in a 0.12-g sample of 95% pure MgCl2 is to be precipitated...

Solutions, Solubility and Concentration. See attached file for full problem description.

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18. Write the reaction
MgCl2 + AgNO3 = 2AgCl + Mg(NO3)2

Molecular weights:
MgCl2 = 24 + 71 = 95 (g/mol)
AgNO3 = 108 + 14 + 48 = 170 (g/mol)
Number of mole of MgCl2 = 0.12*0.95/95 = 0.0012 (mol)
So the number of mole of AgNO3 required to react is also 0.0012 mol.

Volume of ...

Solution Summary

The solution provides detailed analysis and explanations for the solubility problems.

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