Physical Chemistry: Rate Law
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The following reaction A(g) + B(g) →C(g) the mechanism is postulated to occur by way of
the mechanism below:
Step 1. A(g) k-1↔k1 M(g)
Step 2. M(g) + B(g)k2 →C(g)
—————————————
Overall A(g) + B(g) →C(g)
Use steady state approximation to express the rate law in terms of reactants A and B. Also show
under what conditions will the overall rate law take on the form of overall first order rate law and
under what conditions will it be an overall second order rate law.
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Answer
According to steady state approximation whenever a reactive species is produced as intermediate its rate of formation is equal to the rate of decomposition
Here the rate of formation = K1 [A]
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