Purchase Solution

PH, pOH, PKw Calculations

Not what you're looking for?

Ask Custom Question

Calculating pH, POH, PKa, PKb.

59) Calculate the hydrogen ion concentration for a 0.0200 M solution of HCN in 0100 M NaCl.

Attachments
Purchase this Solution
Solution Summary

The expert provides PH, pOH and PKw calculations. The hydrogen ion calculations are determined.

Solution Preview

See the attachment.

HCN(aq) = H+(aq) + CN-(aq)
T=o 1 mol 0 0
T=t (1-x) x mol x ...

Purchase this Solution
Free BrainMass Quizzes
Match Elements with their Symbols

Elements are provided: choose the matching one- or two-letter symbol for each element.

Thermochemistry

The quiz helps in revising basic concepts about thermochemistry.

General Chemistry - Classification of Matter

This test will assess your knowledge on the classification of matter which includes elements, compounds and mixtures.

Periodic table

Organic Chemistry Naming: Alkanes

This is a quiz which is designed to assist students with learning the nomenclature used to identify organic compounds. This quiz focuses on the organic compounds called Alkanes.

View More Free Quizzes
Related BrainMass Solutions

  • Analytical Chemistry Calculations Relationships

    102458 Analytical Chemistry Calculations Relationships Calculation of pH, calculation of pOH, relationship between pH , pOh and pKw See the attachment. 7.

  • Analytical Chemistry Calculations

    102461 Analytical Chemistry Calculations Calculation of pH, calculation of pOH, relationship between pH , pOh and pKw See the attachment. 9.

  • PH, pOH, PKw

    PH, pOH, PKw calculations are provided. Sodium sulfide as a weak acid is determined.

  • Question about PH, pOH, PKw

    102463 Question about PH, pOH, PKw Calculating pH, pOH, pKw; Hydrolysis of salts of: weak acid and strong alkali or strong acid and weak alkali. See the attachment. 15.

  • PH Calculation Basic Principles

    [OH-] = 0.4 mol/dm3 POH = -log10[OH-] = -log10(0.4) = -log10(4 x 10-1) = -log104 + (-log1010-1) = -1(-log1010) - log104 = 1 - 0.6020 POH = 0.3980 Recall that PKw = PH + POH PKw = 14 PH = PKw - POH PH = 14 - 0.3980 = 13.6020 Solution7

  • PH, pOH, PKw

    102464 PH, pOH, PKw Calculating pH, pOH, pKw; Hydrolysis of salts of: weak acid and strong alkali or strong acid and weak alkali. See the attachment.

  • Discussing the pkw Variable

    is 10^(-14) -log kw = -log(10^(-14)) = 14 = pH + pOH, so if you have pH or pOH you have the other through this relation.

  • PH, pOH, PKw

    102471 PH, pOH, PKw Calculating pH, POH, PKa, PKb. See the attachment.

  • PH, pOH, PKw

    102469 PH, pOH, PKw Calculating pH, POH, PKa, PKb. See the attachment.

View More Related Solutions