Explore BrainMass
Share

PCl5 in a heated glass bulb

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

a) A weighted amount of PCl5 is sealed in a 100.0mL glass bulb and heated to 250'C. When the system reaches equilibrium, the pressure in the bulb is 0.895atm. If Kp = 2.15 at 250'C, what is the partial pressure of each of the three gases at equilibrium?

PCL5(g) ===========> PCl3(g) + Cl2(g)

b) Calculate Kc at 250'C.

c) If delta H for the reaction is +87.9 kJ/ mol, calculate Kp at 200'C.

© BrainMass Inc. brainmass.com March 22, 2019, 1:22 am ad1c9bdddf
https://brainmass.com/chemistry/physical-chemistry/pcl5-heated-glass-bulb-534861

Solution Preview

Let Px, Py and Pz be the partial pressures of PCl5, PCl3 and Cl2. For every 'x' mol of PCl3 that forms, 'x' mol of CL2 should also form. Hence Py =Pz

Total pressure = 0.895 atm. Hence Px + ...

Solution Summary

The Kc and Kp for the reaction of PCl5 are calculated.

$2.19