A light bulb has a filament of metal that has an emissivity of 0.3 and a surface area of 5.0 x 10^-5 m^2. It is heated to 2500 degrees Celsius in an environment with a temperature of 25 degrees Celsius. What is the power dissipated through radiation by the filament?
We can use the equation for net flow of heat radiation:
Power = e (sig) A ...
This solution identifies the variables and includes complete calculations and answer.