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# Combustion of Sucrose in a Bomb Calorimeter

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1. Combustion of 2.016 grams of solid sucrose (C6H12O6) at 25 º C in a bomb calorimeter with heat capacity 9550 J K -1 gives a temperature rise of 3.282 º C.

a) Write the balanced equation for the combustion of sucrose
b) What is the work done by the system?
c) What is the heat change per mole of sucrose for the reaction?
d) Find the change in internal energy per mole of solid sucrose for this process

##### Solution Summary

The solution shows how data from a bomb calorimeter can be used to calculate the internal energy of sucrose.

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1. Combustion of 2.016 grams of solid sucrose (C6H12O6) at 25 º C in a bomb calorimeter with heat capacity 9550 J K -1 gives a temperature rise of 3.282 º C.

a) Write the balanced equation for the combustion of sucrose
b) What is the work done by the system?
c) What is the heat change per mole of sucrose for the reaction?
d) Find the change in internal energy per mole of solid sucrose for this process

Solution:
(a) The balanced equation for the combustion of C6H12O6 is:
C6H12O6 + 6 O2  6 H2O + 6 CO2 + ENERGY

(b) w = - PV where w = work and P = pressure and V = change in volume.

In a bomb calorimeter, volume does not change (unless it explodes! ). If there is no change in volume, V = 0, so work = 0.

(c) q(heat) = cT (heat capacity of calorimeter, T is change intemperature)
= 9550. J/K x 3.282 K
= 31340 J (absorbed by calorimeter) (4 significant figures)
Heat generated by ...

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