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Calculating percent by mass

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A 1.248 g sample of limestone rock is pulverized and then treated with 30.00 mL of 1.035 M HCl solution. The excess acid then requires 11.56 mL of 1.010 M NaOH for neutralization.

Calculate the percent by mass of calcium carbonate in the rock, assuming that it is the only substance reacting with the HCl solution.

Please explain the analysis.

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This solution helps calculate percent by mass.

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Mol of HCl initially = 0.030L x 1.035M = 0.03105 mol HCl

Mol of NaOH reacted = Mol of HCl excess = 0.01156L x 1.010M = ...

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