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Acid-base titration & analytical chemistry

A 0.213-g sample of uranyl(VI)nitrate, UO2(NO3)2, is dissolved in 20.0 mL of 1.0 M H2SO4 and shaken with Zn. The zinc reduces the uranyl ion, UO2 (with a charge of 2+), to a uranium ion, Un+ (where n+ is the charge of the uranium ion). To determine the value of n, this solution is titrated with KMnO4. Permanganate is reduced to Mn2+ and Un+ is oxidized back to UO2(with a charge of 2+).
In the titration, 12.47 mL of 0.0173 M KMnO4 was required to reach the equivalence point. Use this information to determine the charge on the ion Un+.

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A 0.213-g sample of uranyl(VI)nitrate, UO2(NO3)2, is dissolved in 20.0 mL of 1.0 M H2SO4 and shaken with Zn. The zinc reduces the uranyl ion, UO22-, to a uranium ion, Un+ (where n+ is the charge of the uranium ion). To determine the value of n, this solution is titrated with KMnO4. Permanganate is reduced to Mn2+ and Un+ is oxidized back to UO2+2.

Solution

In the titration, 12.47 mL of 0.0173 M KMnO4 was required to reach the equivalence ...

Solution Summary

This solution provides step by step calculations for questions involving titration.

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