If we look at the H nmr spectrum, we see a quartet that is around 4.0 ppm. This represents the only CH2 group next to the O of the ester. The oxygen of the ester makes these two protons move to 4.0 ppm. It is split into a quartet by the adjacent CH3 group. The triplet we see is of this same terminall CH3 group. It is split into a triplet by the ...
The solution examines the NMR and infrared spectroscopy.