Purchase Solution

Explain why the 3-pentanol 13C-NMR spectrum contains three peaks while the trans and cis-2-pentene spectra contain five peaks

Not what you're looking for?

Ask Custom Question

A)Explain why the 3-pentanol 13C-NMR spectrum contains three peaks while the trans and cis-2-pentene spectra contain five peaks (note that 13C-NMR gives a peak for each unique carbon, i.e. identical carbons show up as the same peak).

Purchase this Solution
Solution Summary

A)Explain why the 3-pentanol 13C-NMR spectrum contains three peaks while the trans and cis-2-pentene spectra contain five peaks (note that 13C-NMR gives a peak for each unique carbon, i.e. identical carbons show up as the same peak).

Solution Preview

Well, this is not that difficult to understand.

There are only three kinds of carbon atoms in 3-pentanol. Draw it out. You'll see this is so. It's a symmetrical molecule where C1 is identical to C5, C2 is ...

Purchase this Solution
Free BrainMass Quizzes
Periodic table

Thermochemistry

The quiz helps in revising basic concepts about thermochemistry.

Functional groups in Organic Chemistry

You will be tested on the names of functional groups in Organic Chemistry. It is very important to know the functional groups to understand Organic reactions.

General Chemistry - Classification of Matter

This test will assess your knowledge on the classification of matter which includes elements, compounds and mixtures.

Organic Chemistry Naming: Alkanes

This is a quiz which is designed to assist students with learning the nomenclature used to identify organic compounds. This quiz focuses on the organic compounds called Alkanes.

View More Free Quizzes
Related BrainMass Solutions

  • C-13 NMR and GC Spectra of 3-Pentanol and 2-Pentene

    b) Explain why the 3-pentanol 13C-NMR spectrum contains three peaks while the trans and cis-2-pentene spectra contain five peaks (note that 13C-NMR gives a peak for each unique carbon, i.e. identical carbons show up as the same peak).

  • 1H NMR Spectrum Interpretation

    There are three distinct groups in this molecule: benzene ring, vinyl group and -COOH group. In all there should be 6 NMR peaks .2 peaks corresponding to Ar-H, 3 peaks due to the vinyl group and one peak due to -COOH group.

  • NMR spectra of 3,3,5-trimethyl-cyclohexanol

    - and trans-3,3,5-trimethyl- cyclohexanol formed in this reaction, from the area under these C-H peaks.

  • 13C NMR and 1H NMR Equivalency of Carbons and Protons

    For the compound below tell how many signals you would expect the molecule to have in its normal, broadband decoupled 13C NMR spectra. 2. Identify the indicated sets of protons as unrelated, homotopic, enantiotopic, or diastereotopic. 3.

  • Interpretation of 1H NMR 4-vinylbenzoic Acid

    In all there should be 6 NMR peaks .2 peaks corresponding to Ar-H, 3 peaks due to the vinyl group and one peak due to -COOH group. You are getting exactly what is expected.

  • Deriving Unknown Chemical Compound

    The 1H and 13C NMR spectra of the compound are given on the following page. Propose a structure for the unknown compound and assign all peaks in the two NMR spectra.

  • Three 13C and 1H NMR Questions

    147189 Three 13C and 1H NMR Questions. The fullly formatted problems are in the attached file. For the compound below, determine how many peaks would be present in the compound's normal 13C decoupled spectrum.

  • H NMR and C NMR spectra

    122160 H NMR and C NMR Each word document contains one problem. I need the structures that go along with each spectrum. See attached file for full problem description. 1.

  • NMR Splitting and Radical Mechanism

    566256 NMR Splitting and Radical Mechanism 1. Knowing that Jac > Jab > Jbc how many lines (peaks) would be observed for Ha? 2.

View More Related Solutions