I need to: provide an interpretation for all protons in the 1H NMR spectrum of 4-vinylbenzoic acid and indicate how the 1H NMR spectrum of the corresponding methyl ester would differ from that of the acid.
On the 1H spectrum, I see a quartet around 6.8ppm which I don't know where it comes from, because I think it should be a triplet and also why there is two doublets, when I think there should only be one. I can see that the singlet at 7.2ppm is probably the H of -OH. and the two doublets at around 7.5 and 8.0ppm are Ar-H protons. I also need help on the methyl ester part.© BrainMass Inc. brainmass.com October 24, 2018, 7:53 pm ad1c9bdddf
4-Vinylbenzoic acid is an aromatic carboxyllic acid. There are three distinct groups in this molecule: benzene ring, vinyl group and -COOH group. In all there should be 6 NMR peaks .2 peaks corresponding to Ar-H, 3 peaks due to the vinyl group and one peak due to -COOH group. You are getting exactly what is expected. The peak at ...
This Solution contains over 200 words to aid you in understanding the Solution to these questions.
NMR Spectra of a Product
Obtain a 1H NMR spectra of the product in CDCl3 (given with this posting). Integrate the two low-field sets of peaks at 3.8 and 4.2 ppm, analyze the coupling constant (J) patterns to assign the two sets of peaks (as I discussed before, the MNova software auto assigns it for you), and report the percentage distribution of cis- and trans-3,3,5-trimethyl- cyclohexanol formed in this reaction, from the area under these C-H peaks.
I integrated the entire spectra for NMR, I don't know how to assign the coupling constant in mastering nova and have no idea how to solve the percent distribution at all
I have filled in the CG calculations, would you please double check for accuracy?View Full Posting Details