When tert-pentyl bromide is treated with 80% ethanol, the amounts of alkene products indicated below are detected on analysis. Explain why Compound I is formed in far greater amount than the terminal alkene.
CH3CH2C=CH2 (there is also a CH3 single bonded underneath the single C) (8%)
tert-Pentyl alcohol, tert-Pentyl ethyl ether (60%).
Solution includes structural drawings and mechanisms for reaction in illustrating and explaining why compound I is formed in far greater amounts.