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Oxidizing Agents, Bohr vs. Rydberg and the Zeeman Effect

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1. Why is the peroxide anion such a strong oxidizing agent?

2. Describe qualitatively how the conclusions of Bohr and Rydberg are essentially the same?

3. Which property of the hydrogen atom does the Zeeman Effect illustrate? Explain this.

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Solution Summary

The solution gives descriptive explanations to the three conceptual questions posed on the strength of peroxide as an oxidizing agent, the similarities between Bohr and Rydberg's conclusions and how the Zeeman Effect illustrates certain properties of hydrogen.

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Peroxide, O2^(2-) (That's two oxygen atoms with a 2 minus charge) is such a strong oxidizer b/c the average charge per oxygen atom is negative 1. Oxygen prefers to have charge of negative 2.

Also, if you draw the molecular orbital diagram for this, you will see that it is only very weakly bonded, so it will dissociate easily.


They both hypothosized (sp?) that the separation of lines in the spectrum of hydrogen are proportional to 1/n^2. The Balmer-Rydberg equation is ...

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