The minimum frequency of light needed to eject electrons from a metal is called the threshold.
Find the minimum energy needed to eject electrons from a metal with a threshold frequency of 3.27*10^14s^-1.
With what kinetic energy will electrons be ejected when this metal is exposed to light with a wavelength of lamda = 245 nm?
KE_electron = _________ J
Energy is related to frequency via E = hv.
The energy of the ejected electron is the difference between the minimum required energy and the energy of the light. You're given the wavelength of the light (lambda = 245 nm) which you'll need to convert to energy using E = hc/lambda.
Recall that h is Planck's constant (h = 6.626*10^-34 J*s) and c is the speed of light (c=2.998*10^8 m/s).© BrainMass Inc. brainmass.com October 10, 2019, 5:24 am ad1c9bdddf
1. Solving for the minimum energy needed to eject the electron:
E = h?
E = (6.626 × 10-34 J·s)(3.27 x 1014/s)
E = 2.17 x 10-19 J
2. To solve for the ...
This solution provides calculations for various questions involving ejecting electrons with light.