There are two beakers each with distilled water. One has trihydrogen borate + potassium hydroxide (H3BO3 + KOH) and the other has trihydrogen borate + sodium hydroxide (H3BO3 + NaOH).
What are the products that are formed after the solutions are heated and placed in an ice water bath?
Hint: There will be a precipitate.© BrainMass Inc. brainmass.com October 24, 2018, 5:11 pm ad1c9bdddf
Boric acid is not very soluble which means that it won't dissolve well without heating. When you heat the solutions all the molecules break up into their ions. So the H3BO3 breaks up into 3 hydrogen ions and (H+) and one borate ion (BO3-). The NaOH also breaks up into the sodium ion (Na+) ...
The solution briefly explains the properties of the reactants. It also describes he best way to find out if a reaction might occur and breaks up the molecules into ions to help predict the answer.
Determining net ionic equation of a reaction
HINT: Aqueous ionic compounds exist as ions in solution. Start by writing the reactants as individual aqueous ions. Then use the solubility rules (https://sites.google.com/site/chempendix/solubility-chart) to identify any precipitates. Be sure to include phases and charges as necessary in your answer!
Start by writing the reactants as individual aqueous ions.
Ag^+ (aq)+NO^- 3(aq)+Ba^2+(aq)+OH^-(aq)
^ This three is a sub 3.
It is acceptable to ignore coefficients for now, then balance at the very end. Next, check the solubilities (https://sites.google.com/site/chempendix/solubility-chart) of silver hydroxide and barium nitrate. Soluble products should be written as individual aqueous ions. Insoluble products should be written as solid compounds. Finally, cancel out species that appear on both sides of the equation.View Full Posting Details