Purchase Solution

Completing Reactions and Oxidation State

Not what you're looking for?

Ask Custom Question

1. Complete and balance the following reactions.
CaO(s) + H2O(l) →
Mg(s) + H2O(l) ⎯⎯Δ→
Na(s) + xss O2(g) ⎯⎯Δ→

2. V. Deduce the oxidation state of the metal centers in the following 3 compounds.
SrO2 Li3N K2S2

Attachments
Purchase this Solution
Solution Summary

The expert completes and balances reactions. The oxidation state is determined.

Solution Preview

1. Complete and balance the following reactions.

CaO(s) + H2O(l) → Ca(OH)2(aq)

Mg(s) + H2O(l) ⎯⎯Δ→ MgO + H2

4Na(s) + xss O2(g) ⎯⎯Δ→ 2Na2O

Note:
In some ...

Purchase this Solution
Free BrainMass Quizzes
Match Elements with their Symbols

Elements are provided: choose the matching one- or two-letter symbol for each element.

General Chemistry - Classification of Matter

This test will assess your knowledge on the classification of matter which includes elements, compounds and mixtures.

Periodic table

Functional groups in Organic Chemistry

You will be tested on the names of functional groups in Organic Chemistry. It is very important to know the functional groups to understand Organic reactions.

Thermochemistry

The quiz helps in revising basic concepts about thermochemistry.

View More Free Quizzes
Related BrainMass Solutions

  • Oxidation States of Manganese

    Manganese can exist in different oxidation states in different compounds and in KMnO4 it exists in 7+ oxidation state. When KMnO4 reacts with NaHSO3, it gets reduced and goes to different oxidation states depending on the pH of the solution.

  • Molybdenum Enzyme Model Compounds

    State the reasons for your choice and describe, with the aid of diagrams, the mechanism involved clearly stating the oxidation state of the molybdenum centre at each step.

  • Oxidation of Alcohols

    In CH3OH the oxidation state of C is -2 C + (4 x 1) + (1 x -2) = 0 so C = -2 (H is assumed to have an oxidation state of 1 and O has an oxidation state of -2).

  • Voltaic cells: Redox reactions, Oxidation, Reduction

    77594 Voltaic cells: Redox reactions, Oxidation, Reduction (See attached file for full problem description) --- A voltaic cell has been constructed with an aluminum metal electrode in Al3+(aq) in one half-cell and a lead metal electrode in Pb2+(aq

  • Step-wise procedure for balancing redox reactions

    Through inspection of the oxidation states of the elements involved, we realize that manganese is going from an oxidation state of +7 to an oxidation state of +2. On the other hand, carbon is going from +3 to +4.

  • Oxidation States of Elements

    The oxidation state of oxygen is not -6. It is -2. You're forgetting that there are three oxygen atoms in NO3. Therefore, the oxidation state of each oxygen is -2, although as you know, the total of all three would be -6.

  • Determining the Oxidation State of an Element in a Compound

    594671 Determining the Oxidation State of an Element in a Compound How do you determine the oxidation state of an element in a compound? Two well-known compounds KMnO4 and K2Cr2O7 are used as examples.

  • Liquid Phase Oxidation of S(IV) to S(VI) and pH Lowering

    153918 Liquid Phase Oxidation of S(IV) to S(VI) and pH Lowering Write the reactions responsible for the LIQUID PHASE oxidation of S(IV) to S(VI), and show how the oxidation can lead to a decrease in pH of rain water.

  • Balancing Half-Cell Reactions

    Cl2 + 2e- --> 2Cl- Now we must balance the charge on both half reactions by multiplying the oxidation by 1 and the reduction by 5.

View More Related Solutions