Determine the molecular formula of the oxide of phosphorous when it is in its gaseous state.
Temp 200C, pressure 760mmHg, mass 0.568g, volume 99.5cm3© BrainMass Inc. brainmass.com February 24, 2021, 2:26 pm ad1c9bdddf
We know that PV=nRT
P=1 atm (760 mmHG is 1 atm)
V=0.0995 L (99.5 cm3=99,5ml=0.0995 L)
We need n (moles)
So n= PV/RT ...
The solution involves calculations of moles using the gas law, and a subsequent calculation of molar mass.