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Molecular Formula for the Oxide of Phosphorous

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Determine the molecular formula of the oxide of phosphorous when it is in its gaseous state.

Temp 200C, pressure 760mmHg, mass 0.568g, volume 99.5cm3

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We know that PV=nRT
P=1 atm (760 mmHG is 1 atm)
V=0.0995 L (99.5 cm3=99,5ml=0.0995 L)

We need n (moles)
So n= PV/RT ...

Solution Summary

The solution involves calculations of moles using the gas law, and a subsequent calculation of molar mass.

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