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Partial pressure, pressure conversion, application of ideal gas equation, mole and mass calculation.

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Any number of green plants can photosynthesize glucose (C6H12O6) in the presence of carbon dioxide and water, and producing oxygen as the remaining product. 250 ml of oxygen was produced. The oxygen was collected over water at 27C and at a pressure of 755 Torr. The vapor pressure of water at 27C is approximately 26mm Hg. What mass of glucose was produce? How many grams of water were used in this biosynthesis?

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Solution Summary

Partial pressure, pressure conversion, application of ideal gas equation, mole and mass calculation are given.

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Equation for the reaction:
6CO2(g) + 6H2O(l) → C6H12O6(l) + 6O2(g)
Volume of O2 = 250ml = 250cm3
250cm3 = 250 x 10-6m3
T = 27oC = (27 + 273) K = 300K
PT = 755 Torr = 755mm Hg
Psteam = 26mm Hg
PT = Psteam + PO2
755mm Hg = 26mm Hg + PO2
PO2 = 729mm Hg
760mm Hg = 101,325N/m2
1mm Hg = ...

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