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    Kc and Kp of Reverse Reaction

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    The equilibrium constant Kc for the reaction shown below is 3.8 x 10-5 at 727°C.

    I2(g) = 2 I(g)

    Calculate Kc and Kp for the following equilibrium at the same temperature.

    2 I(g)= I2(g)

    Since they give us first rxn Kc do I first take the inverse (to get the Kc for the second rxn)and then figure the Kp? Is this right? Can you show me?

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    Solution Summary

    This solution explains how to calculate Kc and Kp of a reverse reaction in equilibrium.