Calculate the amount of heat that must be absorbed by 10.0 g of ice at -20.0 degrees C to convert it to liquid water at 60.0 degree C.
Specific heat (ice) = 2.1 j/g degree C
Specific heat (water) delta H (fus)= 6.0 kJ/mol© BrainMass Inc. brainmass.com March 4, 2021, 8:42 pm ad1c9bdddf
First calculate the amount of heat needed to raise the temperature of ice from -20.0°C to 0°C:
Q1 = mc_ice *T = 10.0 * 2.1 * [0 - (-20)] = 420 ...
The solution is comprised of detailed steps of calculating the heat energy required to convert 10 grams ice at -20 degrees Celsius to water at 60 degrees Celsius.