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    Gibbs energy of mixing when the partition is removed

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    Consider a container of volume 5.0 L that is divided into two compartments of equal size. In the left compartment there is nitrogen gas at 1.0 atm and 25 degrees C; in the right compartment there is hydrogen at the same Temperature and Pressure. Calculate the entropy and Gibbs energy of mixing when the partition is removed. Assume the gases behave ideally.

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    Solution Preview

    First calculate the number of mole of each gas. Use ideal gas law:PV=nRT
    For Nitrogen:
    P=1atm=101 kPa
    V=2.5 L
    T=25+273=298(K)
    R=8.314(J/molK)
    hence n=PV/RT=101*2.5/(8.314*298)=0.102(mol)

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