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    A 25.0 mg sample of 148/58 CE (t 1/2=48s) undergoes beta decay. After 4.50 min, how much of the original sample is left, what is the product formed and how much of the product is formed?

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    https://brainmass.com/chemistry/chemical-kinetics/beta-decay-product-formed-36083

    Solution Preview

    If it loses an electron Ce-148 becomes Pr-148, or in the way you write it 148/59 Pr.

    Use this equation to find the rate constant:

    ln(2) = kt{1/2}

    k = ln(2)/t{1/2} = 0.69321/48 s = ...

    Solution Summary

    Beta decay is investigated. The solution discusses what is the product formed and how much of the product is formed.

    $2.49

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