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Given k1 & k2, Calculate Equilibrium Constant

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H20(l) f/r H+(aq) + OH-(aq)
k1 is forward and K_1 is reverse
if k1 = 2.4 x 10^-5 s^-1 and K_1=1.3 x 10^11/M *s
Calculate the equilibrium constant K
Calculate k=[H+][OH-] and [H+] and [OH-].

There should be four answers.

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This is kind of a fun problem. It goes to the idea that the rate constants which are not equilibrium constants can be combined in the ratio of forward over reverse to give the equilibrium constant for the dissociation reaction. K = k(forward)/k(reverse) = 2.4/1.3 x ...

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