Given k1 & k2, Calculate Equilibrium Constant
H20(l) f/r H+(aq) + OH-(aq)
k1 is forward and K_1 is reverse
if k1 = 2.4 x 10^-5 s^-1 and K_1=1.3 x 10^11/M *s
Calculate the equilibrium constant K
Calculate k=[H+][OH-] and [H+] and [OH-].
There should be four answers.
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Solution Preview
This is kind of a fun problem. It goes to the idea that the rate constants which are not equilibrium constants can be combined in the ratio of forward over reverse to give the equilibrium constant for the dissociation reaction. K = k(forward)/k(reverse) = 2.4/1.3 x ...
Solution Summary
The solution provides the answers through equations with explanation.
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