# Given k1 & k2, Calculate Equilibrium Constant

H20(l) f/r H+(aq) + OH-(aq)

k1 is forward and K_1 is reverse

if k1 = 2.4 x 10^-5 s^-1 and K_1=1.3 x 10^11/M *s

Calculate the equilibrium constant K

Calculate k=[H+][OH-] and [H+] and [OH-].

There should be four answers.

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#### Solution Preview

This is kind of a fun problem. It goes to the idea that the rate constants which are not equilibrium constants can be combined in the ratio of forward over reverse to give the equilibrium constant for the dissociation reaction. K = k(forward)/k(reverse) = 2.4/1.3 x ...

#### Solution Summary

The solution provides the answers through equations with explanation.

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