At 700 K, the reaction 2SO2(g) + O2(g) = 2SO3(g) has the equilibrium constant Kc = 4.3 x 10^6, and the following concentration are present:[SO2] = 0.010 M:
[SO3] = 10.M : [O2] =0.010 M
When the reaction system reaches equilibrium, what is the SO3 concentration?
Please show work.
For this question you need to set-up the K equation, which is simply the products divided by the reactants, all to the exponents of the coefficients.
K = [SO2]^2[O2]/[SO3]^2
When you plug in all the values you get an equation that looks like this....
K = [0.010]^2[0.010]/^2
but we know that K has to equal 4.3 x 10^6
right now the ...
The solution provides step-by-step calculations for concentrations when a reaction system reaches equilibrium. The concentration of equilibrium constants are determined.