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    At 700 K, the reaction 2SO2(g) + O2(g) = 2SO3(g) has the equilibrium constant Kc = 4.3 x 10^6, and the following concentration are present:[SO2] = 0.010 M:
    [SO3] = 10.M : [O2] =0.010 M
    When the reaction system reaches equilibrium, what is the SO3 concentration?
    Please show work.

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    https://brainmass.com/chemistry/chemical-equilibrium/concentration-reaction-systems-26156

    Solution Preview

    For this question you need to set-up the K equation, which is simply the products divided by the reactants, all to the exponents of the coefficients.

    K = [SO2]^2[O2]/[SO3]^2

    When you plug in all the values you get an equation that looks like this....

    K = [0.010]^2[0.010]/[10]^2

    but we know that K has to equal 4.3 x 10^6

    right now the ...

    Solution Summary

    The solution provides step-by-step calculations for concentrations when a reaction system reaches equilibrium. The concentration of equilibrium constants are determined.

    $2.49

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