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# Bond length, moles, cathode

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1) Which of the following molecules has the shortest bond length

a) N sub 2
b) O sub 2
c) Cl sub 2
d) Br sub 2
e) I sub 2

2) What number of moles of Osub2 his needed to produce 14.2 Grams 0f Psub4Osub10 (molecular mass =284g)from P?

3) If 0.060 faraday is passed through an electrolytic cell containing a solution of In^3+ ions, the maximum number of moles of In that could be deposited at the the cathode is

https://brainmass.com/chemistry/bonding/bond-length-moles-cathodes-14991

## SOLUTION This solution is FREE courtesy of BrainMass!

1)

Its atomic no is the lowest and also it has a triple bond.
The values for bond lengths are:
(A stands for Angstrom)
a) N sub 2- 1.098 A
b) O sub 2 -1.208 A
c) Cl sub 2 -1.89 A
d) Br sub 2 -2.28 A
e) I sub 2 -2.66 A

2)

284 g of Psub4Osub10= 1 mole
Therefore 14.2 g of Psub4Osub10= 14.2/ 284=0.05 mole of Psub4Osub10
Each mole of Psub4Osub10 contains 10 atoms of oxygen= 5 moles of O sub 2
Thus 0.05 mole of Psub4Osub10 will contain = 0.05 x 5 moles of Oxygen= 0.25 moles

Answer: 0.25 moles of Osub2 is needed to produce 14.2 Grams 0f Psub4Osub10

3)

1 Faraday= charge on 1 mole of electrons
0.060 Faraday will deposit 0.060/3= 0.020 moles of Indium (since charge = +3)