relative strong of conjugate base
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17. Using the following Ka values , indicate the correct order of of the conjugate base strength HNO2.
Ka = 4.0 x 10-4
HF. Ka = 7.2 x 10 -4
HCN. Ka = 6.2 x 10-10
A. CN- > NO2- > F- > H2O > CL-
B. CL- > H2O > F- > NO2- > CN-
C. CN- > F- > NO2- > CL- > H2O
D. H2O > CN- > NO2- > F- > CL-
E. None of the above are correct
Explain your sequence.
18. At 0 C , the ion-product of water , Kw , is 1.2 x 10-15. The pH of pure water at 0 degrees C is
A. 1.2
B. 6.88
C. 7.00
D. 7.46
E. 12
Show calculation.
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Solution Summary
The solution explains how to determine the strength of the acid based on its equilibrium constant Ka, in turn, it explains how to find the relative strength of their corresponding conjugate base. Moreover, it shows the calculation of pH of pure water at 0 degrees C (see attachment).
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17. HCl is a strong acid.
The larger of ...
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