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Potassium Hypochlorite

What mass of potassium hypochlorite must be added to 450.0 mL of water to give a solution with pH = 10.20?

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pH = 10.20 thus the pOH = 14 - 10.20 = 3.8
The [OH-] is equal to 10^-3.8 = 1.585 * 10^-4 mol/L
Ka = 4.0 * 10^-8 thus the Kb = 10^-14/(4.0 * 10^-8) = 2.5 * 10^-7
The equilibrium reaction is: OCl- ...

Solution Summary

This solution looks at the mass of potassium hypochlorite to be added to water to give a particular pH.

$2.19