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pH, pOH

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How do I complete this table?

Sodium hydroxide
H = 4.2 x 10^-10
OH = _______
pH = _______
pOH= ________

Hydrocloric Acid
H = _________
OH = _______
pH = _______
pOH= 11.5

Potassium Hydroxide
H = _________
OH = _______
pH = _______
pOH= 2.5

Acetic Acid
ka=1.8 x 10^-5
H = _________
OH = 6.3 x 10^-9
pH = _______
pOH= ________

Ammonium hydroxide
kb = 1.8 x 10^-5
H = _________
OH = _______
pH = 10.2
pOH= ________

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Solution Summary

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Hi,

The formulas to be used to complete the blanks are as follows:
pH = -log[H] = 14 - pOH
pOH = -log[OH] = 14 - pH

Just need to reverse when the other ...

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