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    pH and pOH

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    Here is the pH of each of the following:
    ? pH = log[H3O+] , pH + pOH = 14, [H3O+] * [OH-] = 1.0 X 10^-14
    ? pH = -log(0.001) = 3
    then...
    ? pOH = -log[OH-] = -log(0.001) = 3
    ? pH = 14- pOH = 14 - 3 = 1

    Could you show me a few of the steps between line one and two in both of these conclusions? thanks.

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    https://brainmass.com/chemistry/physical-chemistry/ph-poh-305046

    Solution Preview

    Need help in pH questions?
    Here is the pH of each of the following:
    • pH = log[H3O+] , pH + pOH = 14, [H3O+] * [OH-] = 1.0 X 10^-14
    • pH = -log(0.001) = 3
    then...
    • pOH = -log[OH-] ...

    Solution Summary

    The solution explains the relationships among pH, pOH, hydroxide ion, and H+ in detial.

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