1. A sample of concetrated nitric acid has density of 1.41g/ml and contains 70% HNO3, by mass.
a. What mass of HNO3 is present per litre of solution?(in g/l)
b. What is the molarity of the solution?

2. Calculate each of the following quantities.

a. molarity of a solution prepared by diluting 32.14ml of 0.238M potassium chloride to 150.00ml

b. molarity of a solution prepared by diluting 27.83ml of 0.0682M ammonium sulfate to 500.00ml

c. molarity of sodium ion in a solution made by mixing 3.79ml of0.284M sodium chloride with 500.00ml of 6.51 x 10-3M sodium sulfate(assume volumes are additive)

a) Mass of HNO3 = 70% of 1.47g
= 70/100 x 1.47g = 0.987g
Mass of water = Mass of conc. HNO3 solution - Mass of HNO3
= (1.41 - 0.987)g
= 0.423g
1ml of water weighs approximately 1g
Therefore, 0.423g water has volume of 0.423ml
HNO3 was prepared by dissolving 0.987g HNO3 in 0.423ml of water.
0.423ml of water contained 0.987g HNO3
1ml water =( 0.987/0.423)g
1000ml water = (0.987/0.423)g x 1000
= 2.3333 x 103g/l

Alternatively, Mass Conc.(g/l) = mass in g/volume(l)
= 0.987g
...

Solution Summary

The solution assists with calculating the molarity, mole and dilution in the given problem.

... 2) Calculate the molar concentration of acetic acid at ... can input that number into the before dilution equation and ... per liter 3.5 x 10^-12 moles per liter ...

...Molarity = 0.5222 M mass of formic acid mass percent = mass of solution 0.5222moles of formic ... 1mL × 100% = × × × 1 L of solution 1 mole of formic ...

... in tube 1? Moles can be determined by the molarity and the ... To find that out, we take the moles of NaOH we just ... For every 1:10 dilution, the pH drops by 1 point ...

... The same number of moles of iron ion need to be ... If the molarity of iron is 0.03855 M, then the volume ... of iron solution, you need to calculate dilution for the ...

... True, as concentration changes on dilution. ...Molarity = moles of solute / liters of solution = 0.0100 mol / 10.0L = 0.00100 M. B. What is the pH of the solution? ...

... Calculate the solubility (in moles/liter) if Cu(OH) 2 ... strong monoprotic acid, such as HCL of the same molarity. ... 3. A buffer solution contains .4 mole of formic ...

... Final moles of acetate = original moles of NaOH ( 1:1 mole ratio ... If equal molar amounts of Na2HPO4 and Na3PO4 are mixed in water, calcuate the resulting pH ...

... The mole of 4.71 g of KOH is n = 4.71/56 mol. ... So the molarity of the solution is (1.384V/98 mol) / (0.001 ... the moles of HCl remains the same before and after the ...

... 100ml of a 0.1M acetic acid solution, how much 17.4 Molar acetic acid ... 3. 17.4 M = 17.4 moles/1000mL 0.1 M = 0.1 moles/1000mL. ... so a 1/174 dilution is required. ...

... Now you can use the dilution formula to figure out ...moles of KHP and one significant for moles of NaOH ... significant figure is provided for the molarity of NaOH). ...