freezing point of naphthalene and benzene mixture
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How many grams of naphthalene, C10H8, would you add to 49.5 g of benzene, C6H6 (l), to produce a solution that has the same freezing point as pure water? (Use the data from the table as needed.)
Molal Freezing Point Depression and Molal Boiling Point Elevation Constants:
Solvent Normal Freezing K(fr) Normal Boiling K(br)
Point,C C m^-1 Point, C C m^-1
Acetic acid 16.63 3.90 117.90 3.07
Benzene 5.53 5.12 80.10 2.53
Cyclohexane 6.55 20.0 80.74 2.79
Nitrobenzene 5.8 8.1 210.8 5.24
Water 0.00 1.86 100.00 0.512
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It determines the freezing point of naphthalene and benzene mixture. The solution is detailed and has a rating of '5/5'.
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In the dilute ideal solutions, the extent of freezing-point depression is directly proportional to the molal concentration of the solution
deltaTf = Kf · m
where deltaTf = Tf(pure solvent benzene) - Tf(solution as water) = 5.53 - 0 = ...
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