See the attached file.
1. i. Clearly draw the structure of the Lopinavir. (You can find the structure using any internet
ii. What is the use of Lopinavir? (maximum: two sentences)
iii. On the structure that you have drawn label the following groups, if present: one phenyl ring,
one benzyl ring, one amide, one aldehyde, one ketone, one ester, one alkyne, one alkene,
one 1o alcohol, one 2o alcohol, one 3o alcohol, one 1o amine, one 2o amine, one 3o amine and
2. The mass spectrum below corresponds to C7H7X: benzyliodide, benzylbromide, benzylchloride or benzylfluoride.
i. Calculate the degree of unsaturation for these compounds.
ii. Based on your analysis of the mass spectrum, what is the molecular formula and structure
of the compound? Give the reason for your answer using data from the spectrum below. In
addition, in your answer state why you were able to determine that the other halogens
were not present. You are not required to analyze the peaks below m/z 75. (maximum: 4
iii. What is the m/z‐value of the base peak?
iv. How is the ion for the base peak formed? In your answer, show the mechanism for formation of this ion.© BrainMass Inc. brainmass.com October 25, 2018, 2:13 am ad1c9bdddf
Please find the complete solutions attached.
1. Reference: http://www.mcld.co.uk/hiv/?q=lopinavir
Lopinavir is an antiretroviral developed by Abbott to treat HIV/AIDS and is administered as a coformulation with an earlier Abbott drug, Ritanovir (this helps bioavailablity).
i. Degree of Unsaturation = [2 + (2 x #Carbons) + #Nitrogens - #Hydrogens - #Halogens]/2
= [2 + (2 x 7) + 0 - 7 - 1]/2
The dominant molecular ion corresponds to 126 m/z which is the calculated molecular mass for this compound. The other major signal at 91 m/z ...
The solution examines spectrum and reactions for chemical structures.
Acid and base: Structures, Reactions, and NMR Spectrums
1. If 3-bromo-1-propanol is treated with NaOH, a compound of molecular formula C3H6O is formed. Suggest a structure for this product.
2. What product(s) would you expect to form when tetrahydrofuran is treated with excess hydroiodic acid (HI)?
3. Write a suitable mechanism for the cleavage of butyl isopropyl ether with HI at 100 degrees C to form exclusively isopropyl alcohol and 1-iodobutane. Explain why butyl alcohol and isopropyl iodide are not formed
in the reaction.
4. There are only four lines in the aromatic region of the fully 1 H decoupled13C NMR spectrum of propyl p-tolyl aromatic carbon atoms. Explain.View Full Posting Details