Calculate [H+], [HA] and [H2A] for a weak dibasic acid.
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Calculate [H+], [HA] and [H2A] for a 0.1M solution of the weak dibasic acid H2A.
Given: H2A=H+ + HA- Ka1=2.0 X 10-5
HA- = H+ + HA- Ka2=1.00 X 10-12
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Solution Summary
For this question, one must be proficient with the general formula used to do a simple weak acid Ka = x^2/C-x.
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For this question, one must be proficient with the general formula used to do a simple weak acid.
Ka = x^2/C-x
This come from the equilibrium equation,
H2A --> H+ + HA-
Initial C 0 0
Change -x x x
-----------------------------
Equil ...
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