Explore BrainMass

Resultant Force on Eyebolt

Not what you're looking for? Search our solutions OR ask your own Custom question.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

Determine the resultant force acting on the eyebolt shown in the attached figure, as a result of the four forces shown, both analytically and graphically. Compare and comment on the two results.

See the attached file.

SOLUTION This solution is FREE courtesy of BrainMass!

Convention for unit vector
Upward (+y axis): j; downward (-ve y axis): -j; right side (=ve x axis): i; left side (-ve x axis): -i
Hence, foces in vector form in cartesian system

F1 = 800kN (-j)
F2 = 400 kN (-j)
F3 = 300kN (-i cos(50) - j sin(50)) = 300 (- 0.643 i - -.766 j) = (- 192.84 i -229.81j)
F4 = 20 kN (-i cos(45) + j sin(45)) = 20 (- 0.70 i + 0.707 j) = (-14.14 i + 14.14 j)

Note: Fi == Fi vector; |Fi| == magnitude of Fi vector

Resultant force,
R = F1 + F2 + F3 + F4
= - 800 j - 400 j + (- 192.84 i -229.81j) + (-14.14 i + 14.14 j)
= - 206.98 i - 1415.77 j

Magnitude of resultant force,
|R| = sqrt (206.98^2 + 1415.77^2) = 1430.82 kN --Answer

Direction:
theta (-ve x to -ve y direction) = tan-1(1415.77/206.98) = 81.685 degree --Answer

For graphical part, see attachment.
Note: Graphical part: Please measure the length of the resultant, and see result. Result should be more or less similar to what we are getting here. There may be a small error in graphical method, because of inaccuracy in drawing exact angle and length.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!