magnification of the picture

Related BrainMass Solutions

• Size of cell based on picture is determined.

  31950 Size of cell based on picture is determined. You have been given a picture of a cell; the magnification of the picture is 8000 X. The cell in this picture is 2 cm in length.

• Ray Optics: Combination of lens and mirror

  (refer to attached picture) 1.) At what distance from the lens does the first image (from the lens) form? 2.) What is the magnification of the first image? 3.) What is the object distance to be used to calculate the image formed by the mirror?

• Focal length and power of lens, Index of refraction of block material

  Height of the object=5cm Height of the image =24mm=2.4 cm Magnification =2.4/5=-0.48 because the image is real and inverted The distance between the lens and the object=u=-2m (negative by the sign convention) The magnification of the lens negative

• Microscopy: total magnification, depth of field

  What is the total magnification of images viewed under each of the four lenses of a light microscope? Magnification of a specimen viewed by a light microscope = ocular magnification multiplied by magnification by the objective lens.

• Magnification of an object 4.9 cm high, but appears 16 cm high

  There are no units in this problem, since magnification is simply a number. size of object (O) = 4.9 cm size of image (I) = 16 cm magnification (m) = I/O = 16/4.9 = 3.265 The magnification of an object 4.9 cm high is examined.

• Optics: Calculate the magnification when viewing a stamp with a magnifying glass

  The magnification is calculated.

• Magnification in a compound microscope.

  A real inverted and enlarged Image is formed by the objective whose lateral magnification is given by mo = Where h is the height of the object and h' is the height of the image.

• The Magnification of a Lens

  78016 The Magnification of a Lens An object is in front of a converging lens (f = 0.30 m). The magnification of the lens is m = -4.0.

• Converging Lenses and Final Image

  Total Magnification = Magnification of First* Magnification of second lens = (150/30)*(21/133.5) = x 0.787 This solution determines where the final image of an object will be that is formed by the second of the converging lens