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Ray Optics: Combination of lens and mirror

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An object is placed 12.0 cm in front of a converging lens of focal length 5.00 cm. A concave mirror with radius of curvature 20.0 cm is located 30.0 cm in back of the lens as shown. (refer to attached picture)

1.) At what distance from the lens does the first image (from the lens) form?
2.) What is the magnification of the first image?
3.) What is the object distance to be used to calculate the image formed by the mirror?
4.) What is the distance from the mirror to the image formed by the mirror?
5.) What is the magnification of the mirror image compared to the original object seen by the lens?
6.) Is the image formed by the mirror real or virtual?
7.) Find the location and magnification of the final image

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Solution Summary

A converging lens and a concave mirror are placed at a distance. Seven parts are solved for different distances and magnifications.

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See Also This Related BrainMass Solution

Refraction, net magnification and internal reflection

1. An object of height 2 cm is placed 10 cm in front of a mirror. What type of
mirror with what radius of curvature is needed to create an upright image with a
height of 5 cm?

2. A ray of light strikes the midpoint of one face of an equilateral glass prism
(n = 1.6) at an angle of incidence of 50°. Trace the path of the ray through the
glass and find the angles of incidence and refraction at each interface.
Ignore any dispersion that might take place.

3. A converging lens of focal length 10 cm is placed 35 cm in front of a concave
mirror with a radius of curvature of 20 cm. An object is placed 13 cm in front of
the lens. Locate and describe the final image, and determine its net magnification.
(ray diagram not required)

4. A ray of light passes between layers of material as shown. Find the minimum value for θ_2 and the corresponding value of θ_1 that will result in total internal reflection at the glass/air interface.

See document attached for diagrams.

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