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    Equilibrium Concentration from Keq and Initial Concentration

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    Part 1: what is equilibrium concentrations and concentration ratios of glucose-6-phosphate/glucose-1-phosphate in the phosphoglucomutase reaction when the initial concentration of glucose-6-phosphate is (a) .01 M and (b) 10^-3 M. The Keq for the reaction below is 19.

    Glucose-1-phosphate ---> glucose-6-phosphate

    Part 2: what are the equilibrium concentrations and concentration ratios of acetate/acetic acid in the ionization of acetic acid when the initial concentration of acetic acid is (a) .01 M, and (b) 10^-3 M. The keq for the reaction below is 1.62 x 10^-5.

    Acetic acid --->acetate + H+

    Why were the ratios the same in the first part but different in Part 2?

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    https://brainmass.com/biology/biological-chemistry/equilibrium-concentration-keq-initial-concentration-148564

    Solution Preview

    Part 1: What is equilibrium concentrations and concentration ratios of glucose-6-phosphate/glucose-1-phosphate in the phosphoglucomutase reaction when the initial concentration of glucose-6-phosphate is (a) .01M and (b) 10^-3 M. The Keq for the reaction below is 19.

    a)

    Glucose-1-phosphate (G1P) ----> glucose-6-phosphate (G6P)
    Initial conc (M) 0.0 0.01
    Final conc (M) x 0.01 - x

    The [G6P] will go down by the same amount that [G1P] will go up until they get to equilibrium. Now we can solve for x.

    K = [Products] = [G6P] [Reactants] [G1P]
    19 = (0.01 -x)/x
    19x = 0.01 -x
    20x = 0.01
    x = 0.0005

    At equilibrium [G1P] = 0.0005 M and [G6P] = 0.0095 M.
    The ...

    Solution Summary

    This solution shows how to calculate equilibrium concentrations from initial concentrations.

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